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0.25x^2+0.65x-1.67=0
a = 0.25; b = 0.65; c = -1.67;
Δ = b2-4ac
Δ = 0.652-4·0.25·(-1.67)
Δ = 2.0925
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.65)-\sqrt{2.0925}}{2*0.25}=\frac{-0.65-\sqrt{2.0925}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.65)+\sqrt{2.0925}}{2*0.25}=\frac{-0.65+\sqrt{2.0925}}{0.5} $
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